Fahrenheit VS Celsius... Can someone tell me how this problem works?

On the Celsius scale, the temperature from the freezing point of water to the boiling point of water ranges 100 degrees. However, the same temperature change on the Fahrenheit scale is represented by 180 degrees. Suppose an object檚 temperature changes from 10掳C to 50掳C, representing a change of 40掳C. Calculate the

object檚 temperature change in degrees Fahrenheit.



When i changed 10 and 50 degrees to Fahrenheit and subtracted, I got 72 which was right. My friend instead directly changed the 40 degrees C to F and he got 104. What happened?Fahrenheit VS Celsius... Can someone tell me how this problem works?
40(9/5) = 72 degrees FFahrenheit VS Celsius... Can someone tell me how this problem works?
Your friend made a mistake.Fahrenheit VS Celsius... Can someone tell me how this problem works?
you did it correctly, you have to take both temperature changes and then subtract them.Fahrenheit VS Celsius... Can someone tell me how this problem works?
180/100 = 1.8 degrees Fahrenheit/degree Celsius



(1.8掳F/掳C) * 40掳C = 72掳F That's what your friend should have done. What he got is the equivalent temperature of 40掳C in 掳F !!!!



You were asked to find out what the a 40 change in celsius was in fahrenheit, not what 40 celsius were in fahrenheits.



You see, 32掳F = 0掳C , so 40 degrees celsius equals 1.8*40 + 32 = 104 掳F which what your friend got! You got it right because you subracted the 32掳F.



Think of these temperatures scales as stairs. The Celsius one starts at a higher point than the Fahrenheit one (32掳F = 0掳C) and has bigger steps (1.8 times bigger, to be precise).Fahrenheit VS Celsius... Can someone tell me how this problem works?
acutally ur friend is right in one way . here is the equation for C to F

F = 1.8C + 32

F = 1.8*40 + 32

F = 104

but since its asking for change urs is rightFahrenheit VS Celsius... Can someone tell me how this problem works?
The formula for conversion is

F-32/9 =C/5 Put the figures and solve the equation.Fahrenheit VS Celsius... Can someone tell me how this problem works?
The conversion from Celsius to Fahrenheit is:



C *(9/5) +32 = F



So,



10 * 9/5 +32 = 50



and



50 * 9/5 + 32 = 112





112 - 50 = 72



However your friend only looked at the difference and did this



40 * 9/5 + 32 = 104



but this is not correct because the 32 is a constant. You would need to subtract 32 from the answer to get 72.





Think of it like this, if you subtract the first two answers



112 - 50 you are really subtracting



(50*9/5 + 32) - (10*9/5 + 32) and the 32's will cancel.



And you would get



40*9/5 = 72Fahrenheit VS Celsius... Can someone tell me how this problem works?
Amok's reasoning is perfect. Give him 10 points.