Find the F and C intercepts of the line described in this equation?

To change the temprature from degrees Fahrenheit to degrees celsius, use formula:

c=5/9(F-32).



I need to find the F and C intercepts. I would like someone to show me how to do this.



Thanks a bunch :)

CristyFind the F and C intercepts of the line described in this equation?
1. Find the %26quot;C%26quot; intercept. First: replace %26quot;0%26quot; with the %26quot;F%26quot; variable %26gt;



C = 5/9(0 - 32)



Sec: multiply the numerators %26gt;



C = (5/9)(-32)

C = -160/9



2. Find the %26quot;F%26quot; intercept. First: replace %26quot;0%26quot; with the %26quot;C%26quot; variable %26gt;



0 = 5/9(F - 32)



Sec: use distribution %26gt; multiply 5/9 with both terms in the parenthesis %26gt;



0 = (5/9)F - (5/9)(32)

0 = (5/9)F - 160/9



Third: eliminate fractions %26gt; multiply the denominator by everything and cancel %26quot;like%26quot; terms %26gt;



9(0) = (9)(5/9)F - 9(160/9)

0 = 5F - 160



*Add 160 to both sides %26gt;



0 + 160 = 5F - 160 + 160

160 = 5F



*Solve for %26quot;F%26quot; by isolating it %26gt; divide both sides by 5 %26gt;



160/5 = 5F/5

32 = F

F = 32Find the F and C intercepts of the line described in this equation?
I think you want to find the temperature at which F is equal to C so just set C = F and solve the equation F = 5/9(F -32) this will give the temperature at which they are equal. I will give you a hint. It is very cold.Find the F and C intercepts of the line described in this equation?
to find the intercepts you just set the other variable to zero



i.e. to find the F intercept, set c=0 then solve for F



0=5/9(F-32) --%26gt; 9/5=(F-32) -----%26gt; F=(9/5)+32 ---%26gt;

F=169/5 or about 33.8



just do the same for cFind the F and C intercepts of the line described in this equation?
At c = 0, you get F-intercept = 32.

At F = 0, you get c-intercept = -160/9



F = 9c/5 + 32Find the F and C intercepts of the line described in this equation?
The F and C intercepts are just like the x and y intercepts.



The C-intercept is the value of C where F = 0:



C = 5/9(0 - 32) = -160/9 = -17 7/9 degrees Celsius.



The F-intercept is the value of F where C = 0:



0 = 5/9(F - 32)



Multiply both sides by 9/5:



0 = F - 32

F = 32 degrees Fahrenheit (of course!)Find the F and C intercepts of the line described in this equation?
c=5/9(f-32)

to find the f intercept, set c=0

0=5/9 (f-32) divide by 5/9

0=f-32 add 32 to each side

f=32



to find the c intercept set f=0

c=5/9(0-32)=-5*32/9=-160/9=-17.77....Find the F and C intercepts of the line described in this equation?
for F intercept putC=0

0=(5/9)(F-32)

multiplying by (9/5)

0=F-32

adding 32

F=32



for C intercept put F=0

C=(5/9)(-32)

C=-160/9Find the F and C intercepts of the line described in this equation?
c=5/9(f-32) *9

9c=5(f-32)

9c=5f-160 by arrange the equation

5f-9c=160 /160

f/32+c/(-160/9)=1

then f_intercept is 32 %26amp;c_intercept is -160/9Find the F and C intercepts of the line described in this equation?
When F=0, C = (5/9)(-32) = -17 7/9



When C = 0,

0 = (5/9)(F-32)

0 = F - 32

32 = F ....... by definition, in F system water freezes at 32, in C system, at 0.